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Comment obtenir les coordonnées d'un élément svg?

J'utilise d3 pour tracer une ligne à partir d'une position relative de svg et souhaite par conséquent accéder aux coordonnées de l'élément lui-même. J'ai essayé quelque chose comme ceci (où "ceci" fait référence à l'élément)

 .attr("x1", this.x)
 .attr("y1", this.y)

mais x1 et y1 valent par défaut zéro. Quelle est la bonne façon d'obtenir les coordonnées de l'élément svg?

MODIFIER:

Voici mon (sur demande) mon code entier. J'essaie d'implémenter ceci sur l'arborescence réductible, où je trace une ligne lorsque je survole la souris au-dessus d'un nœud de cercle. Le point de départ de la ligne doit provenir du cercle sur lequel je clique et le point final doit être un point fixe sur le plan svg.

<!DOCTYPE html>
<html>
  <head>
    <meta http-equiv="Content-Type" content="text/html;charset=utf-8">
    <script type="text/javascript" src="d3.v3.js"></script>
    <script type="text/javascript" src="d3.layout.js"></script>
    <style type="text/css">

.node circle {
  cursor: pointer;
  fill: #fff;
  stroke: steelblue;
  stroke-width: 1.5px;
}

.node text {
  font: 10px sans-serif;
}

path.link {
  fill: none;
  stroke: #ccc;
  stroke-width: 1.5px;
}

    </style>
  </head>
  <body>
    <div id="chart"></div>
    <script type="text/javascript">

var m = [20, 120, 20, 120],
    w = 2240 - m[1] - m[3],
    h = 800 - m[0] - m[2],
    i = 0,
    duration = 500,
    root;

var tree = d3.layout.tree()
    .size([h, w]);

var diagonal = d3.svg.diagonal()
    .projection(function(d) { return [d.y, d.x]; });

var vis = d3.select("#chart").append("svg")
    .attr("width", w + m[1] + m[3])
    .attr("height", h + m[0] + m[2])
  .append("g")
    .attr("transform", "translate(" + m[3] + "," + m[0] + ")");

function loadData(json) {
    root = json;
    d3.select("#processName").html(root.text);
    root.x0 = h / 2;
    root.y0 = 0;
    root.children.forEach(collapse);
    update(root);  
}

function collapse(d) {
    if (d.children) {
      d._children = d.children;
      d._children.forEach(collapse);
      d.children = null;
    }
 };

// Toggle children on click.
function click(d) {
  if (d.children) {
    d._children = d.children;
    d.children = null;
  } else {
    d.children = d._children;
    d._children = null;
  }
  update(d);
}

function update(source) {

  // Compute the new tree layout.
  var nodes = tree.nodes(root).reverse();

  // Normalize for fixed-depth.
  nodes.forEach(function(d) { d.y = d.depth * 180; });

  // Update the nodes…
  var node = vis.selectAll("g.node")
      .data(nodes, function(d) { return d.id || (d.id = ++i); });

  // Enter any new nodes at the parent's previous position.
  var nodeEnter = node.enter().append("g")
      .attr("class", "node")
      .attr("transform", function(d) { return "translate(" + source.y0 + "," + source.x0 + ")"; })
      .on("click", click);

  nodeEnter.append("circle")
      .attr("r", 1e-6)
      .style("fill", function(d) { return d._children ? "lightsteelblue" : "#fff"; })
    .on('mouseover', function(d, i){
        var dataset = [1,2,3,4]                                    // HERE
        vis.selectAll("line")                                      // HERE
            .data(dataset)                                 // HERE
            .enter()                                       // HERE
            .append("line")                                // HERE
            .attr("x1", this.x)                            // HERE'S THE PROBLEM FOR PERRY
            .attr("y1", this.y)                            // HERE'S THE PROBLEM FOR PERRY
            .attr("x2", 500)                               // HERE
            .attr("y2", 500)                               // HERE
            .style("stroke", "rgb(6,120,155)");}           // HERE
       ); 

  nodeEnter.append("text")
      .attr("x", function(d) { return d.children || d._children ? -10 : 10; })
      .attr("dy", ".35em")
      .attr("text-anchor", function(d) { return d.children || d._children ? "end" : "start"; })
      .text(function(d) { return d.name; })
      .style("fill-opacity", 1e-6);

  // Transition nodes to their new position.
  var nodeUpdate = node.transition()
      .duration(duration)
      .attr("transform", function(d) { return "translate(" + d.y + "," + d.x + ")"; });

  nodeUpdate.select("circle")
      .attr("r", 4.5)
      .style("fill", function(d) { return d._children ? "lightsteelblue" : "#fff"; });

  nodeUpdate.select("text")
      .style("fill-opacity", 1);

  // Transition exiting nodes to the parent's new position.
  var nodeExit = node.exit().transition()
      .duration(duration)
      .attr("transform", function(d) { return "translate(" + source.y + "," + source.x + ")"; })
      .remove();

  nodeExit.select("circle")
      .attr("r", 1e-6);

  nodeExit.select("text")
      .style("fill-opacity", 1e-6);

  // Update the links…
  var link = vis.selectAll("path.link")
      .data(tree.links(nodes), function(d) { return d.target.id; });

  // Enter any new links at the parent's previous position.
  link.enter().insert("path", "g")
      .attr("class", "link")
      .attr("d", function(d) {
        var o = {x: source.x0, y: source.y0};
        return diagonal({source: o, target: o});
      })
    .transition()
      .duration(duration)
      .attr("d", diagonal);

  // Transition links to their new position.
  link.transition()
      .duration(duration)
      .attr("d", diagonal);

  // Transition exiting nodes to the parent's new position.
  link.exit().transition()
      .duration(duration)
      .attr("d", function(d) {
        var o = {x: source.x, y: source.y};
        return diagonal({source: o, target: o});
      })
      .remove();

  // Stash the old positions for transition.
  nodes.forEach(function(d) {
    d.x0 = d.x;
    d.y0 = d.y;
  });

};

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      {"name": "DateInterpolator", "size": 1375},
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      {"name": "MatrixInterpolator", "size": 2202},
      {"name": "NumberInterpolator", "size": 1382},
      {"name": "ObjectInterpolator", "size": 1629},
      {"name": "PointInterpolator", "size": 1675},
      {"name": "RectangleInterpolator", "size": 2042}
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    {"name": "ISchedulable", "size": 1041},
    {"name": "Parallel", "size": 5176},
    {"name": "Pause", "size": 449},
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      {"name": "DelimitedTextConverter", "size": 4294},
      {"name": "GraphMLConverter", "size": 9800},
      {"name": "IDataConverter", "size": 1314},
      {"name": "JSONConverter", "size": 2220}
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    {"name": "DataField", "size": 1759},
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38
Perry

La façon de déterminer les coordonnées dépend de l'élément avec lequel vous travaillez. Pour circles par exemple, les attributs cx et cy déterminent la position centrale. De plus, vous pouvez avoir un translation appliqué via l'attribut transform qui modifie le point de référence de toutes les coordonnées.

La plupart des méthodes utilisées en général pour obtenir les coordonnées de l'écran ne fonctionnent pas pour les SVG. De plus, vous pouvez ne pas vouloir de coordonnées absolues si la ligne que vous voulez tracer se trouve dans le même conteneur que les éléments qu’elle connecte.

Modifier:

Dans votre code particulier, il est assez difficile d’obtenir la position du nœud car elle est déterminée par une traduction de l’élément parent. Vous devez donc obtenir l'attribut de transformation du nœud parent et en extraire la traduction.

d3.transform(d3.select(this.parentNode).attr("transform")).translate

Jsfiddle de travail ici .

24
Lars Kotthoff

La méthode element.getBoundingClientRect() renvoie les coordonnées correctes d'un élément par rapport à la fenêtre, que le svg ait été mis à l'échelle et/ou traduit.

Voir cette question et réponse .

Bien que getBBox () fonctionne pour un espace non transformé, si l'échelle et la traduction ont été appliquées à la présentation, elles ne seront plus précises. La fonction getBoundingClientRect () a bien fonctionné pour moi dans un projet de mise en page forcée lorsque les fonctions de panoramique et de zoom sont activées, où je souhaitais attacher des éléments HTML Div en tant qu'étiquettes aux nœuds au lieu d'utiliser des éléments de texte SVG.

56
t.888

Vous pouvez utiliser la fonction getBBox () pour obtenir le cadre de sélection du chemin. Cela vous donnera la position et la taille du rectangle le plus étroit pouvant contenir le chemin rendu.

L'utilisation de cette méthode par rapport aux valeurs x et y présente l'avantage de fonctionner avec tous les objets graphiques. Il y a plus d'objets que de chemins sans x et y, par exemple les cercles qui ont cx et cy à la place.

7
Lucky

J'utilise la fonction de consolidation, comme suit:

 element.transform.baseVal.consolidate()

Les valeurs .e et .f correspondent aux coordonnées x et y

4
john ktejik

je peux le gérer comme ça;

svg.selectAll("rect")
    .data(zones)
    .enter()
    .append("rect")
    .attr("id", function (d) { return "zone" + d.zone; })
    .attr("class", "zone")
    .attr("x", function (d, i) {
        if (parseInt(i / (wcount)) % 2 == 0) {
            this.xcor = (i % wcount) * zoneW;
        }
        else {
            this.xcor = (zoneW * (wcount - 1)) - ((i % wcount) * zoneW);
        }

        return this.xcor;
    })

et plus vous pouvez trouver la coordonnée x

svg.select("#zone1").on("click",function(){alert(this.xcor});
1
Görkem