web-dev-qa-db-fra.com

Obtenir le jeton de notification push - iOS 10, Swift 3

Comment obtenir le jeton de périphérique du nouveau xCode 8, Swift 3 dans iOS 10?

Voici le code pour enregistrer la notification:

func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {

        DispatchQueue.main.async {
            let settings = UIUserNotificationSettings(types: [.badge, .sound, .alert], categories: nil)
            UIApplication.shared.registerUserNotificationSettings(settings)
        }
        return true
    }

func application(_ application: UIApplication, didRegister notificationSettings: UIUserNotificationSettings) {
        if notificationSettings.types != UIUserNotificationType() {
            application.registerForRemoteNotifications()
        }
    }

Ici, pour obtenir le jeton, mais le message d'erreur suivant s'affiche "Impossible d'appeler l'initialiseur pour le type 'UnsafePointer' avec une liste d'arguments de type '(UnsafeRawPointer)'":

func application(_ application: UIApplication, didRegisterForRemoteNotificationsWithDeviceToken deviceToken: Data) {
        let chars = UnsafePointer<CChar>((deviceToken as NSData).bytes)
        var token = ""

        for i in 0..<deviceToken.count {
            token += String(format: "%02.2hhx", arguments: [chars[i]])
        }

        print("Registration succeeded!")
        print("Token: ", token)
    }

Quelqu'un peut-il aider à le résoudre?

Merci

push-notificationnotificationsswift3ios10
19
user831098

Cette méthode peut résoudre votre problème dans iOS 10 et supérieur:

func application(_ application: UIApplication, didRegisterForRemoteNotificationsWithDeviceToken deviceToken: Data) {
    var token = ""
    for i in 0..<deviceToken.count {
        token = token + String(format: "%02.2hhx", arguments: [deviceToken[i]])
    }
    print(token)
}
34
chirag shah
var pushToken = String(format: "%@", deviceToken as CVarArg)
pushToken = pushToken.trimmingCharacters(in: CharacterSet(charactersIn: "<>"))
pushToken = pushToken.replacingOccurrences(of: " ", with: "")
11
Emre

Swift 3 exemple tiré de raywenderlich.com .

func application(_ application: UIApplication, didRegisterForRemoteNotificationsWithDeviceToken deviceToken: Data){
    let tokenParts = deviceToken.map { data -> String in
        return String(format: "%02.2hhx", data)
    }  
    let token = tokenParts.joined()
    print(token)
}
5
Etienne Martin

Face au même problème, c'est la seule chose qui m'a aidé:

func application(_ application: UIApplication, didRegisterForRemoteNotificationsWithDeviceToken deviceToken: Data) {
    let token = String(format: "%@", deviceToken as CVarArg)
        .trimmingCharacters(in: CharacterSet(charactersIn: "<>"))
        .replacingOccurrences(of: " ", with: "")
}
3
Ivan

Code de travail pour obtenir un jeton de notification Push - iOS 11 ou supérieur, Swift 4

Demander la permission de l'utilisateur 

func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {

    let notificationTypes: UIUserNotificationType = [UIUserNotificationType.alert,UIUserNotificationType.badge, UIUserNotificationType.sound]
    let pushNotificationSettings = UIUserNotificationSettings(types: notificationTypes, categories: nil)

    application.registerUserNotificationSettings(pushNotificationSettings)
    application.registerForRemoteNotifications()

    return true        
}

Obtention d'un jeton de périphérique 

func application(_ application: UIApplication, didRegisterForRemoteNotificationsWithDeviceToken deviceToken: Data) {

    let token = deviceToken.map { String(format: "%02.2hhx", $0) }.joined()
    print(token) 
}

En cas d'erreur 

func application(_ application: UIApplication, didFailToRegisterForRemoteNotificationsWithError error: Error) {

    print("i am not available in simulator \(error)")
}
1
Nikunj Kumbhani

Le snnipet ci-dessous travaille avec la solution Eric Aya: 

let token = deviceToken.reduce("", {$0 + String(format: "%02X", $1)})

Merci pour toute aide :)

1
user831098

Une ligne: 

func application(_ application: UIApplication, didRegisterForRemoteNotificationsWithDeviceToken deviceToken: Data) {
    let apnsDeviceToken = deviceToken.map {String(format: "%02.2hhx", $0)}.joined()
}

De ce tutoriel.

0
ScottyBlades

Cela pourrait fonctionner: 

let chars = UnsafePointer<CChar>((deviceToken as NSData).bytes.assumingMemoryBound(to:CChar.self))

Merci!

0
user6880304